Information about train from Bethesda to Columbia. The great state of railways and its reliability make the train one of the safest transportation systems to travel the distance that separates in train Bethesda and Columbia.
During the travel by train from Bethesda to Columbia passengers can relax. Other reason for choosing train to travel from Bethesda to Columbia is the price, because the price of the train ticket is only $148.17 CAD. This price is approximated and the train company could change it. Ask to the train company in order to get the oficial information.
According to our database, the best route to go from Bethesda to Columbia is through Burke. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
You can find the most accurate information for the route Bethesda MD - Burke VA by clicking here
If you want to get cheap train tickets from Bethesda to Columbia we recommend that you book in advance as the best Amtrak Northeast Regional tickets sell out fast.The cheapest ticket is usually $148.17 CAD and the most expensive one to go to Columbia is approximately $150.86 CAD. .Remember that you must also add the cost of the journey: Bethesda -> Burke
The first trains for the route we propose are:
Bethesda -> Burke: -
Burke -> Columbia: 10:36
The companies that can help you are: Amtrak Northeast Regional.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Bethesda -> Burke
2.- Burke -> Columbia
The approximate distance between the two places is 761 km. With the route we propose, it will take approximately 13h 49m (plus the time it takes to you to make: Bethesda -> Burke).