| Train Ticket Price: | $614.91 CAD |
|---|---|
| Avg. Train Duration: | 124h 23m |
| Train Companies: | Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Jacksonville |
| Trains arrive in: | Lemoore |
Information about train from Jacksonville to Lemoore. The great state of railways and its reliability make the train one of the safest transportation systems to travel the distance that separates in train Jacksonville and Lemoore.
During the travel by train from Jacksonville to Lemoore passengers can relax. Other reason for choosing train to travel from Jacksonville to Lemoore is the price, because the price of the train ticket is only $614.91 CAD. This price is approximated and the train company could change it. Ask to the train company in order to get the oficial information.
According to our database, the best route to go from Jacksonville to Lemoore is through Arcadia. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Jacksonville Station
Arcadia Station
59h 45m
$352.91 CAD
Arcadia Station
Lemoore Station
64h 38m
$261.99 CAD
If you want to get cheap train tickets from Jacksonville to Lemoore we recommend that you book in advance as the best Amtrak tickets sell out fast.The price of the ticket is usually $614.91 CAD.
The first train leaves at 11:15 from Jacksonville and costs $352.91 CAD while the last one arriving at Lemoore costs $261.99 CAD and it is at 12:40.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Jacksonville -> Arcadia
2.- Arcadia -> Lemoore
The approximate distance between the two places is 4415 km. With the route we propose, it will take approximately 124h 23m.