| Train Ticket Price: | $315.2 CAD |
|---|---|
| Avg. Train Duration: | 48h 36m |
| Train Companies: | Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Marshall |
| Trains arrive in: | Baton Rouge |
Information about train from Marshall to Baton Rouge. The great state of railways and its reliability make the train one of the safest transportation systems to travel the distance that separates in train Marshall and Baton Rouge.
During the travel by train from Marshall to Baton Rouge passengers can relax. Other reason for choosing train to travel from Marshall to Baton Rouge is the price, because the price of the train ticket is only $315.2 CAD. This price is approximated and the train company could change it. Ask to the train company in order to get the oficial information.
According to our database, the best route to go from Marshall to Baton Rouge is through Hammond. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Marshall, TX (MHL)
Hammond, LA (HMD)
41h 54m
$274.79 CAD
Hammond, LA (HMD)
Baton Rouge, LA (BTR)
6h 42m
$40.41 CAD
If you want to get cheap train tickets from Marshall to Baton Rouge we recommend that you book in advance as the best Amtrak tickets sell out fast.The price of the ticket is usually $315.2 CAD.
The first train leaves at 19:31 from Marshall and costs $274.79 CAD while the last one arriving at Baton Rouge costs $40.41 CAD and it is at 20:10.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Marshall -> Hammond
2.- Hammond -> Baton Rouge
The approximate distance between the two places is 445 km. With the route we propose, it will take approximately 48h 36m.